Fix some small issues

sections/Auswertung.tex

@@ -9,7 +9,7 @@
 First the resolution limit has to be measured:
 
 \begin{align*}
-    B_{1} & = 0,3 \cdot 10⁻³ m \\
+    B_{1} & = 0,3 \cdot 10^-3 m \\
     B_{2} & = 0,6 \cdot 10^-3 m \\
     B &= (0,45 \pm 0,15) \cdot 10^-3 m
 \end{align*}

sections/Physical-Principals.tex

@@ -92,7 +92,7 @@ Based on the equation $\ref{3}$ the calculation of the magnification of the ocul
 
 \label{3.1}
 \begin{align*}
-  \gamma_{ok} &= frac{a_{0}}{g} \\
+  \gamma_{ok} &= \frac{a_{0}}{g} \\
   &= \frac{a_0}{f_{ok}} \tag{3.1}
 \end{align*}
 
@@ -100,8 +100,8 @@ For $\gamma_{ok}$ at the distance of $a_{0}$ ($\gamma_{ok}(a_{0})$) the equation
 
 \label{6}
 \begin{align*}
-  frac{1}{f} &= frac{1}{g} + frac{1}{b} \tag{6} \\
-  frac{1}{g} &= frac{1}{f} + frac{1}{a_{0}} 
+  \frac{1}{f} &= \frac{1}{g} + \frac{1}{b} \tag{6} \\
+  \frac{1}{g} &= \frac{1}{f} + \frac{1}{a_{0}} 
 \end{align*}
 
 The final formula for $\gamma_{ok}$ is then as follows:
@@ -135,7 +135,7 @@ The minimum distance $d_{min}$ is then calculated thus, A being the numerical ap
 
 \label{8}
 \begin{align*}
-  d_{min} &= frac{\lambda}{A} + frac{1}{b} \tag{8} \\
+  d_{min} &= \frac{\lambda}{A} + \frac{1}{b} \tag{8} \\
   A &= n \cdot sin(\epsilon) \tag{8.1} 
 \end{align*}